please answer this ques
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is the question this 1- tan²(45-A) = 2 sin A
lets consider 45-A as B
then,
1 - tan² B = 2 sin a
1 - tan²B = L H S
1 - tan²B= sec²B (sec²B- tan²B= 1)
sec²B = L H S
2 sin A = R H S
lets consider 45-A as B
then,
1 - tan² B = 2 sin a
1 - tan²B = L H S
1 - tan²B= sec²B (sec²B- tan²B= 1)
sec²B = L H S
2 sin A = R H S
pragya8:
No you have written wrong ques. but thanks.
i am sorry
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