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1/(1+sinA)+1\(1-sinA)=2 sec^2A
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komalsingrajput:
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Answered by
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FROM LHS
= 1/(1- sinA) +1/(1+sinA)
=(1+sinA+1-sinA)/(1-sinA)(1+sinA)
=2/(1-sin^2A)
here we used (a+b)(a-b)
=a^2-b^2
=2/cos^2 A
here 1-sin^2A=cos^2A
=2sec^2 A here 1/cos^2A
= sec^2A
=RHS
= 1/(1- sinA) +1/(1+sinA)
=(1+sinA+1-sinA)/(1-sinA)(1+sinA)
=2/(1-sin^2A)
here we used (a+b)(a-b)
=a^2-b^2
=2/cos^2 A
here 1-sin^2A=cos^2A
=2sec^2 A here 1/cos^2A
= sec^2A
=RHS
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