Math, asked by Anonymous, 7 months ago

please answer this question

1. Baichung's father is 26year younger than Baichung's grandfather and 29 years older than Baichung. The sum of the age of all the three is 135 years. what is the age of each one of them.​

Answers

Answered by Anonymous
3

Answer:

Baichung's fathers age = ¥

grandfather age. = ¥+26

Baichung's age. = ¥ -29

¥ + (¥+26) + (¥-29) = 135

Answered by ItzEnchantedGirl
8

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}

\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}

A.T.Q :

\longmapsto\tt{x+x-26+x-55=135}

\longmapsto\tt{3x-81=135}

\longmapsto\tt{3x=135+81}

\longmapsto\tt{3x=216}

\longmapsto\tt{x=\cancel\dfrac{216}{3}}

\longmapsto\tt\bf{x=72}

Value of x is 72 .

Therefore :

\longmapsto\tt{Age\:of\:his\:Grandfather=x}

\longmapsto\tt\bf{72\:yrs}

\longmapsto\tt{Age\:of\:his\:Father=72-26}

\longmapsto\tt\bf{46\:yrs}

\longmapsto\tt{Age\:of\:Baichung=72-55}

\longmapsto\tt\bf{17\:yrs}

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