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Let l be length and b be breadth of a rectangle ; then
b = l-3
l = b+3
Area of rectangle = 4 + Area of triangle
l×b = 4+(1/2 × base × height)
lb = 4+(1/2 × b × 12)
lb = 4+6b
(b+3)b = 4+6b
b^2 + 3b = 4+6b
b^2-3b-4 = 0
b^2-4b+1b-4 = 0
b(b-4) +1(b-4) = 0
(b+1)(b-4) = 0
b = -1 & 4
As the breadth can never be negative
therefore b = 4 m
l = b+3
l = 4+3
l = 7
hence the length of a rectangle is 7m and breadth is 4m
b = l-3
l = b+3
Area of rectangle = 4 + Area of triangle
l×b = 4+(1/2 × base × height)
lb = 4+(1/2 × b × 12)
lb = 4+6b
(b+3)b = 4+6b
b^2 + 3b = 4+6b
b^2-3b-4 = 0
b^2-4b+1b-4 = 0
b(b-4) +1(b-4) = 0
(b+1)(b-4) = 0
b = -1 & 4
As the breadth can never be negative
therefore b = 4 m
l = b+3
l = 4+3
l = 7
hence the length of a rectangle is 7m and breadth is 4m
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