Math, asked by Namya1209, 10 months ago

Please answer this question​

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Answered by anu24239
2

ANSWER....

y =  \frac{4 + x}{4 - x}  \\  \\ we \: know \: that \: 4 - x \: is \: not \: equal \:  \\ to \: zero \: so \: we \: can \: put \: any \: value \:  \\ of \: x \: except \: 4 \: so \: domain \: is \: all \\ real \: number \: except \: 4 \\  \\ y =  \frac{4 + x}{4 - x}  \\  \\ y(4 - x) = 4 + x \\  \\ 4y - xy = 4 + x \\  \\ 4(y - 1) = x(y + 1) \\  \\ 4 \frac{(y - 1)}{(y + 1)}  = x \\  \\ to \:  find \: range \: of \: a \: question \: you \:  \\ can \: convert \: the \: equation \: in \: y \:  \\  \\ so \: we \: know \: that \: y + 1 \: is \: not \: equal \: to \: 0 \:  \\ so \: the \: range \: of \: the \: question \: is \: all \: real \: no. \\ except \:  - 1

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