Question

please answer this question..

Answer 1

let r be the common radius of a sphere , a cone and cylinder
height of the sphere = its diameter =2r
height of the cone = height of cylinder = height of sphere=2r

let l be the slant height of the cone =l =√r²+h²

= √r²+(2r)² =√5 *r
S1 = CSA of sphere = 4πr²
S2 =CSA of cylinder = 2πrh =2πr*2r = 4πr²

S3 = CSA of cone = πrl = πr*√5*r = √5πr²

ratio of CSA
S1:S2:S3 = 4πr² : 4πr²:√5 πr²

= 4:4:√5
2) v1=volume of sphere= 4/3*pi*r^3
v2=volume of cylinder=(pi*r^2*h)
v3= volume of cone=(pi*r^2*h)/3
ratio of volumes
v1:v2:v3= 4/3*pi*r^3:pi*r^2h:(pi*r^2*h)/3

=4/3*pi*r^3:pi*r^2*2r :(pi*r^2*2r)/3
=4/3pi*r^3: 2*pi*r^3 : 2/3* pi*r^3
after cancellation
=4/3: 2: 2/3
=12:6:2
=6:3:1