Math, asked by namitasharma34, 11 months ago

please answer this question

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Answered by rohitanand22112003

0

Answer:

AGE OF AFTAB DAUGHTER = X

AFTAB - Y

Y-7=7(X-7)

Y=7X -49+7

Y=7X-42

LET THIS BE EQ1

THE

Y+3=3(X+3)

Y+3=3X+9

Y=3X+6

SUBSTITUE EQ 1 IN Y

7X-42=3X+6

4X=48

X=12

Y=12*3+6

=42

SO AFTAB OS 42YRS AND DAUHTER IS 12YRS

Step-by-step explanation:

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