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AGE OF AFTAB DAUGHTER = X
AFTAB - Y
Y-7=7(X-7)
Y=7X -49+7
Y=7X-42
LET THIS BE EQ1
THE
Y+3=3(X+3)
Y+3=3X+9
Y=3X+6
SUBSTITUE EQ 1 IN Y
7X-42=3X+6
4X=48
X=12
Y=12*3+6
=42
SO AFTAB OS 42YRS AND DAUHTER IS 12YRS
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