Question

please answer this question​

Answer 1

Answer:

perimeter of rectangle APQD = 80

Sidex and 2x

80=2(x+3x)

x +3x=40

4x=40

x=10

Hence the side of the square

=3x=30cm

Perimeteral the SQUARE ABCD

= 30x4=120cms

Answer 2

Given,

ABCD is a square.

PB = 2AP

The perimeter of rectangle APQD = 80 cm.

To find,

The perimeter of ABCD.

Solution,

We can easily solve this numerical problem by following the given steps.

Now,

PB = 2AP --- equation 1

ABCD is a square.

Then,

AB = BC = CD = AD

AB = AP + PB

AB = AP + 2AP ( Putting the value of PB from equation 1)

AB = 3 AP

Let's take the side AP to be x cm.

AB = 3x cm --- equation 2

The perimeter of rectangle APQD = 80 cm

2 (AD + AP) = 80 cm

AD + AP = 80/2

3x + x = 40 ( AD is equal to AB as the four sides of the square are equal)

4x = 40

x = 10 cm

Putting the value of x in equation 2, we get

AB = 3x

AB = 3 × 10

AB = 30 cm

The perimeter of square ABCD (P) = 4×Side

P = 4 × side

P = 4 × AB

P = 4 × 30

P = 120 cms

Hence, the perimeter of square ABCD in cms is 120 (option B).