Question

Please answer this question​

Answer 1

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Answer=40°

∆ABC=180 "A" "B" INERSECT WITH "P"

SO, ∆ABC DIVIDED INTO TWO ∆

SO, ∆ABC=180 ,∆APB=180, 180+180=360

ANGLE APB =80°

ANGLE AOC =140°

CAB+80°+140°=360

CAB+220 =360

CAB =360-220

CAB =40°