Question

Please answer this question

Answer 1

Given triangles ABC and DBC are on the same base BC.

∠A = ∠D = 90°.

⇒ ∠AEB = ∠DEC {Vertically Opposite angles are equal}

⇒ ΔABC ~ ΔDBC {AA Similarity}

⇒ (AE/DE) = (BE/CE)

⇒ AE * CE = BE * DE

Hope it helps!

Answer 2

Answer:

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