Question

please answer this question

Answer 1

hey friend, here is the solution
BD=EC(given)
add DE on both the sides
BD+DE=EC+DE
we get BE=DC consider it as equation 1
in ∆ADE
AD=AE(Given )
so angle ADE= angle AED(angles opposite to equal sides of a ∆ are equal) consider it as equation 2
now in ∆ABE and ∆ADC
BE=DC(using equation 1)
angle ADE=Angle AED(using equation 2)
AE=AD(given )
so ∆ABE is congruent to ∆ADC by SAS criterion
therefore, AB=AC (c.p.c.t)