Question

Please answer this question ​

Answer 1

Answer:

a\4-b\2+1

=a²\16+(-b\2)² +(1)²+2\1×a\4×(-b\2)+2(-b\2)×1+2×1×a\4

a²\16+b²\4+1-ab\4-b+a\2

Answer 2

we know (a+b+c)2 has a formula that is A square+B square+C square+ 2ab + 2ba +2ac s here comes the solution
(1/4-1/b+1)square.
(1/4)square-(+1/2b)+1+ 2×1/4+(-1/2b+2×-(1/2)b×1+2×1×1/4=1/16-1/4b square+1 -1/4-1b+1/2