Math, asked by rahulsharma0139, 10 months ago

please answer this question​

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Answered by rishu6845
1

Answer:

x = 14 / 15 , y = 1 / 5

Step-by-step explanation:

Given---->

( 3x - 2iy ) ( 2 + i )² = 10 ( 1 + i )

To find ---> Value of x and y.

Solution---> We know that ,

i = √-1

Squaring both sides we get,

=> i² = ( - √1 )²

=> i² = -1

ATQ,

( 3x - 2iy ) ( 2 + i )² = 10 ( 1 + i )

We have an identity as follows,

( a + b )² = a² + 2ab + b² , we get,

=> ( 3x - 2iy ) { ( 2 )² + ( i )² + 2 ( 2 ) ( i ) } = 10 ( 1 + i )

=> ( 3x - 2iy ) ( 4 + i² + 4i ) = 10 + 10 i

Putting i² = -1 , we get,

=> ( 3x - 2iy ) ( 4 - 1 + 4i ) = 10 + 10 i

=> ( 3x - 2iy ) ( 3 + 4i ) = 10 + 10 i

=> 9x + 12ix - 6iy - 8 i² y = 10 + 10 i

Putting i² = -1 , we get,

=> 9x + 12ix - 6iy - 8 ( -1 ) y = 10 + 10i

=> 9x + i ( 12x - 6y ) + 8y = 10 + 10i

=> ( 9x + 8y ) + i ( 12x - 6y ) = 10 + 10i

Comparing real and imaginary part , we get,

9x + 8y = 10 ..................................( 1 )

12x - 6y = 10 ................................( 2 )

Multiplying equation ( 1 ) by 6 and equation ( 2 ) by 8 and then adding we get,

6 ( 9x + 8y ) + 8 ( 12x - 6y ) = 10 × 6 + 10 × 8

=> 54x + 48y + 96x - 48y = 60 + 80

=> 150 x = 140

=> x = 140 / 150

=> x = 14 / 15

putting x = 14 / 15 in equation ( 1 ) , we get,

9x + 8y = 10

=> 9 ( 14 / 15 ) + 8y = 10

=> 42 / 5 + 8y = 10

=> 8 y = 10 - 42/5

=> 8y = ( 50 - 42 ) / 5

=> 8y = 8 / 5

=> y = 1 / 5

#Answerwithquality

#BAL

Answered by Anonymous
34

Answer:

Step-by-step explanation:

Given---->

( 3x - 2iy ) ( 2 + i )² = 10 ( 1 + i )

To find ---> Value of x and y.

Solution---> We know that ,

i = √-1

Squaring both sides we get,

=> i² = ( - √1 )²

=> i² = -1

ATQ,

( 3x - 2iy ) ( 2 + i )² = 10 ( 1 + i )

We have an identity as follows,

( a + b )² = a² + 2ab + b² , we get,

=> ( 3x - 2iy ) { ( 2 )² + ( i )² + 2 ( 2 ) ( i ) } = 10 ( 1 + i )

=> ( 3x - 2iy ) ( 4 + i² + 4i ) = 10 + 10 i

Putting i² = -1 , we get,

=> ( 3x - 2iy ) ( 4 - 1 + 4i ) = 10 + 10 i

=> ( 3x - 2iy ) ( 3 + 4i ) = 10 + 10 i

=> 9x + 12ix - 6iy - 8 i² y = 10 + 10 i

Putting i² = -1 , we get,

=> 9x + 12ix - 6iy - 8 ( -1 ) y = 10 + 10i

=> 9x + i ( 12x - 6y ) + 8y = 10 + 10i

=> ( 9x + 8y ) + i ( 12x - 6y ) = 10 + 10i

Comparing real and imaginary part , we get,

9x + 8y = 10 ..................................( 1 )

12x - 6y = 10 ................................( 2 )

Multiplying equation ( 1 ) by 6 and equation ( 2 ) by 8 and then adding we get,

6 ( 9x + 8y ) + 8 ( 12x - 6y ) = 10 × 6 + 10 × 8

=> 54x + 48y + 96x - 48y = 60 + 80

=> 150 x = 140

=> x = 140 / 150

=> x = 14 / 15

putting x = 14 / 15 in equation ( 1 ) , we get,

9x + 8y = 10

=> 9 ( 14 / 15 ) + 8y = 10

=> 42 / 5 + 8y = 10

=> 8 y = 10 - 42/5

=> 8y = ( 50 - 42 ) / 5

=> 8y = 8 / 5

=> y = 1 / 5

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