Question

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Answer 1

Answer:

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Answer 2

Answer:

Given, thickness of iron =3cm

         external diameter = 56cm

              Length of tube = 182cm

We know,

 volume of hollow cylinder = πh(R²−r²)

∴ internal diameter = external diameter−2×thickness of iron

                              = 56−2×3

                              = 56−6

                              = 50cm

=> Outer radius(R) = 56÷2 = 28cm

      inner radius(r) = 50÷2 = 25cm

∴ Volume of hollow cylinder = πh(R²−r²)

                                       = 3.14×182(28²−25²)

                                       = 3.14×82×159

                                       = 90865.32cm³       Answer

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