please answer this question
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Answer:
Kx^2 +(2k+4)x+9=0
Step-by-step explanation:
kx^2+2kx+4x+9=0
we knw that there are equal roots..so
D=b^2-4ac=0
=(2k)^2-4(k)(9)=0
4k^2-36k=0
4k(k-9)=0
either 4k=0 or (k-9) =0
4k=0
k=0
k-9 =0
k=9
hope it Will help you
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