Math, asked by rimshaaijaz3, 11 months ago

please answer this question​

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Answered by cr7sharma
1

Answer:

Kx^2 +(2k+4)x+9=0

Step-by-step explanation:

kx^2+2kx+4x+9=0

we knw that there are equal roots..so

D=b^2-4ac=0

=(2k)^2-4(k)(9)=0

4k^2-36k=0

4k(k-9)=0

either 4k=0 or (k-9) =0

4k=0

k=0

k-9 =0

k=9

hope it Will help you

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