Math, asked by bvspawan, 10 months ago

please answer this question ​

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Answered by SUMANTHTHEGREAT
1

x=a(secx+tanx)^2

x^2=(a^2)((secx+tanx)^4)

y=b(secx-tanx)^2

y^2=(b^2)((secx-tanx)^4)

(x^2)(y^2)=(a^2)((secx+tanx)^4)(b^2)((secx-tanx)^4)

=((ab)^2)((secx)^2-(tanx)^2)^4

=((ab)^2)(1^4)

=((ab)^2)

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Answered by surendrasahoo
2

Your answer is in the page below.

❣HOPE IT IS HELPFUL. ❣

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