Math, asked by poorvi8161, 9 months ago

please answer this question​

Attachments:

Answers

Answered by KoFiLLer
1

Please check the image to understand the question.

We need to prove,

5AB^{2} = 5AC^{2} + BC^{2}

Now, the black colored stuff represent AB^{2},

the red colored stuff represents AC^{2}.

The green, is the difference of the two above.

Using Pythagoras theorem we find AB^{2}, and substitute the give condition,

DB = 3/2 CD

then, we find AC^{2}, and subtract the two.

Now, we have after taking the '-' common from the equation in the image,

AB^{2} - AC^{2} = 5/4 CD^{2}

Multiply 5 to get to the required equation.

5AB^{2} - 5AC^{2} = 25/4 CD^{2} ------------- I

Now, BC^{2} = [CD + 3/2 CD]^{2} = 25/4 CD^{2}

Hence, I can be deduced as,

5AB^{2} = 5AC^{2} + BC^{2}

Hence, proved.

Attachments:
Similar questions