please answer this question - 16 and 15 and 12
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Answered by
1
In 16.
AD=2EB(given)
DA is parallel BE
angle FEB=angle FAD(corr. angles)
angle FDA=angle FBE
therefore, triangle FDA is simm to triangle FBE
hence
FE/AF =FB/DF =EB/DA = 1/2
AD=2EB(given)
DA is parallel BE
angle FEB=angle FAD(corr. angles)
angle FDA=angle FBE
therefore, triangle FDA is simm to triangle FBE
hence
FE/AF =FB/DF =EB/DA = 1/2
Answered by
6
In 12.....
x^2-2x+1
x+4(x^3+2x^2-9x+1)
(x^3+4x^2-9x+1)
(2x^2-9x+1)
(2x^2-8x)
( x+1)
(x+4)
reminder= 3
Quotient=x^2-2x+1
thanks
x^2-2x+1
x+4(x^3+2x^2-9x+1)
(x^3+4x^2-9x+1)
(2x^2-9x+1)
(2x^2-8x)
( x+1)
(x+4)
reminder= 3
Quotient=x^2-2x+1
thanks
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