Question

please......
answer this question
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Answer 1

Answer:

let the number of boys be 'x' and girls be 'y'

ATQ:

1st case

x=160+y

2nd case

45%(x+y)=y

$\frac{45}{100} (x + y) = y$

$\frac{9}{20} \times (x + y) = y$

$9x + 9y = 20y$

$9x = 11y$

$9(160 + y) = 11y$

$1440 + 9y = 11y$

$2y = 1440$

$y = 720$

=>Boys = 720+160

x =880

=>Girls, y=720