Question

please answer this question ​

Answer 1

Answer:

40H.

Explanation:

The self inductance of a wire will be having a formulae of self inductance, L which is = μ(permeability)*n(number of turns per unit length)V(A*l which is volume or area * length).

The self inductance only depends on the physical quantities, the number of turns per unit length of the wire will be 1 since it is a single wire. So on substituting the values will get that the self inductance L= μnAl or 20000*1*2*10^-3 which will be 40H.

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Answer 2

Answer:

hope this attachment helps u buddy

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