please answer this question
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i forgot this answer sorry
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Let p(y) = ay² + ay + 3
g(y) = y² + y + b
Since 1 is a root of the p(y) and g(y),
p(1) = 0
g(1) = 0
p(1) = a+a+3 = 0
2a = -3
a = -3/2
g(1) = 1+1+b = 0
b = -2
Therefore, ab = -3/2 × -2
= 3
Option a(3) is the correct answer
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