Math, asked by Sushmarai231982, 10 months ago

please answer this question

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Answers

Answered by gyanaseelanff4023

0

Step-by-step explanation:

2(3x-5y-20=0)

=6x-19y-40=0

by subtracting bothe the terms:

(6x-19y-40=0)-(6x-10y+40=0)

we get,

-9y-80=0

-9y=80

y=80/-9

by substituting,

3x-5*80/9-20=0

3x -400/9 =20

3x = 20*9/400

3x = 9/20

x = 3/20

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