Question

Please answer this question

Answer 1

Answer:

BC=27

Step-by-step explanation:

In ΔABP

AP²=AB²+BP²                                (hypotenuse²=perpendicular²+base²)

17²=8² + BP²

BP²=17² - 8²

BP²=289 - 64

BP²=225

BP=15

In ΔDCP

DP²=DC² +PC²                                (hypotenuse²=perpendicular²+base²)

20²=16² + PC²

PC²=20² - 16²

PC²=400 - 256

PC²=144

PC=12

BC=PC + BP

BC=12+15

BC=27

Answer 2

Answer:

hypothesis²=side²+side²

so for Triangle ABP

hypothesis=17cm

ab=8cm

BP=?

17²=8²+BP²

17² - 8²=BP²

289-64

225=BP²

√225=15

BP=15

similarly

triangle BPC

20²=16²+PC²

400-256=PC²

144=PC²

PC=√144

12=PC

soBP+PC=15+12

BP+PC=27