Science, asked by lovelysharmals, 10 months ago

please answer this question ​

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Answered by Hidisha
0

Answer:

In a zince lead cell the reaction is

pb2+(aq)+Zn(s)?pb(s)+zn2+(aq)Eo=0.637v

Explanation:

The concentration of products zn2+is 1m

The concentration of reaction (eq)(/rm((p))((/rm(b))^(2+

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