Question

please answer this question​

Answer 1

Step-by-step explanation:

x=-b+-√b2-4ac/2a

= -1+-√1squre-4(a+2)(a+1)/2(1)

=-1+-√1+4a squre+12a+8/2

=-1+-√4a squre+12a+9/2

= -1+-√(2a+3)squre/2

= -1+-(2a+3). x=2a+2/2 and x=-2a-4/2

x=a+1x =-(a+2)

the roots of x squre+x-(a+2)(a+1)=0

are(a+1)and -(a+2)

Answer 2

Answer:

Thanks for free point(◔‿◔)