Question

please answer this question

Answer 1

s=2n^2+3n
sum of only first term will be first term itself so put n=1
s=5
therefore first term =5
Now sum of 2 terms=put n=2
s=14
I. e. , first term +second term =14
5+x=14
x=second term =9
and common diff=second term -first term =9-5=4
therefore
a=5,d=4
sixteenth term=a+15d
=5+15(4)
=5+60=65