Question

Please answer this question

Answer 1

Answer:

cot@ = 2/3

using Pythagoras,

x² = (2)² + (3)² = 4+9 = 13

x = √13

sin@ = 3/√13 , cos@=2/√13

=> (4sin@ - 3cos@)/(2sin@ + 6cos@)

=> ( 4(3/√13) - 3(2/√13) )/ (2(3/√13) + 6(2/√13) )

√ 13 common & cut

=> ( 4(3) - 3(2) )/(2(3) + 6(2) )

=> (12-6)/(6+12)

=> 6/18

=> 1/3