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a x² + b x + c = 0.
roots are α and β.
given α - β = 2 --- (1)
also α + β = -b/a ---(2)
α β = c/a --- (3)
(1) and (2) ==> 2α = 2 - b/a = (2a -b)/a
Substitute in (2): β = -b/a - (2a - b)/2a = -1 - b/2a = -(2a +b)/2a
(3) ==> -(2a - b) (2a + b) / (4a²) = c/a
b² - 4 a² = 4 a c
b² = 4a (a +c)
roots are α and β.
given α - β = 2 --- (1)
also α + β = -b/a ---(2)
α β = c/a --- (3)
(1) and (2) ==> 2α = 2 - b/a = (2a -b)/a
Substitute in (2): β = -b/a - (2a - b)/2a = -1 - b/2a = -(2a +b)/2a
(3) ==> -(2a - b) (2a + b) / (4a²) = c/a
b² - 4 a² = 4 a c
b² = 4a (a +c)
kvnmurty:
:-)
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