please answer this question
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Q= q1 + q2 + q3
q1= const = c
q2 = k1 y^1/2
q3 = k2 y^1/3
60 - c - k1 = k2 ...... (1)
230 = c + 8k1 + 4(60 -c - k1)
k1 = ( 3c - 10)/4
Putting the value of k2 in eq (1)
k2= 60 - c - {(3c - 10) /4}
660 = c + 27( 3c - 10)/4 + 9× [60 - c - {(3c - 10) /4}]
2640 = 85c - 63c + 1980
c = 660/22
c = 30
q1= const = c
q2 = k1 y^1/2
q3 = k2 y^1/3
60 - c - k1 = k2 ...... (1)
230 = c + 8k1 + 4(60 -c - k1)
k1 = ( 3c - 10)/4
Putting the value of k2 in eq (1)
k2= 60 - c - {(3c - 10) /4}
660 = c + 27( 3c - 10)/4 + 9× [60 - c - {(3c - 10) /4}]
2640 = 85c - 63c + 1980
c = 660/22
c = 30
HimanshuHK:
Ammm! constant is 30!
Oh ! I'm sorry I'll try once more
oh! No need of sorry!
I did it I made a calculation mistake before
Ok.
please tell me.. how we can do it?
I've edited the ans , I cant attach a photo now I guess
So do the favour with photo!
i will be thankful for it!
hi
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