Question

please answer this question​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

20. tanA=4/3

sinA=4/5

cosA=3/5

secA=5/3

cosecA=5/4

i)LHS:secA-cosecA=(5/3)-(5/4)=5(1/3-1/4)=5(1/12)=5/12

secA+cosecA=(5/3+5/4)=5(1/3+1/4)=5*7/12=35/12

sqrt((5/12)/(35/12))=sqrt(1/7)=1/sqrt(7)=RHS

ii) 1-sinA=1-(4/5)=1/5

1+cosA=1+(3/5)=8/5

sqRT(1/8)=1/2sqrt(2)=RHS