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therefore Sample space is 'S' and n(S)=3+4+7=14
event A : drawing a red ball
therefore n(A)=3
therefore P(A)=n(A)/n(S)
=3/14
event A: drawing a black ball
therefore n(B)=7
therefore p(B)=n(B)/n(S)
=7/14
=1/2
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Total outcomes = 3+4+7 = 14.
the probability of drawing red or a black balls:- total favourable outcomes =3+7=10.
p(E) = No|| of favourable outcomes
total possible outcomes
= 10/14 = 5/7.
I hope it is helpful to you.
God knows best
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