Question

please answer this question.​

Answer 1

ye konsi class ka question hai

Answer 2

5.6 cm

Step-by-step explanation:

Given:

Diameter of cylindrical vessel = 7 cm.

Diameter of marbles = 1.4 cm

To find:

The height of water level increased by the immersion of marbles.

Solution:

Diameter of marbles = 1.4 cm

Radius of marbles = 1.4/2 = 0.7 cm

Therefore, volume of marbles = volume of sphere

$\frac{4}{3} \pi r {}^{3} \\ \\ = \frac{4}{3} \pi {0.7}^{3} \: \: cm {}^{3} \\ \\ \frac{4}{3} \pi \times \frac{7}{10} \times \frac{7}{10} \times \frac{7}{10} \: \: \: cm {}^{3}$

Again,

Diameter of cylindrical vessel = 7 cm

Radius of cylindrical vessel = 7/2 cm

Let, the water raised by h cm by the immersion of 150 marbles.

Volume of raised water = Volume of cylindrical vessel

$\pi {r}^{2} h \\ \\ \pi \times (\frac{7}{2} ) {}^{2} \times h \\ \\ \pi \frac{7}{2} \times \frac{7}{2} \times h \: \: cm {}^{3}$

A.T.Q

Volume of raised water = Volume of 150 marbles

$\pi \frac{7}{2} \times \frac{7}{2} \times h = 150 \: \times \frac{4}{3} \pi \times \frac{7}{10} \times \frac{7}{10} \times \frac{7}{10} \\ \\ \cancel{\pi} \: \frac{ \cancel{7}}{2} \times \frac{ \cancel{7}}{2} \times h =15 \times \frac{4}{3} \cancel{\pi} \times \frac{ \cancel{7}}{10} \times \frac{ \cancel{7}}{10} \times {7}\\ \\ \frac{h}{4} =5 \times \frac{28}{10 \times 10} \\ \\ h = \frac{20 \times 28}{10 \times 10} \\ \\ h = \frac{2 \times 28}{10} \\ \\ h = 5.6$

Therefore, the required answer is 5.6 cm.