Physics, asked by jyothishmayi, 1 year ago

please answer this question ​

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Answered by beastboy1
0

Answer:

1/Rp= 1/6+1/2

1/Rp=4/6

1/Rp=2/3

Rp=3/2

Rs=3/2+6

Rs=15/2

Rs=7 1/2(d)

Answered by paritoshprasad077
1

Answer:

d) 7*1/2 Ω

Explanation:

It is given that the 6Ω & 2Ω resistor are in parallel . They are in series combination with 6Ω resistor .

We know that ,(In parallel)

1/Req = 1/6 + 1/2

= (1 + 3)/6

Req = 6/4 = 3/2Ω

Also,(In series)

Req = 3/2 + 6

= 15/2 = 7*1/2Ω

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