please answer this question
Attachments:
![](https://hi-static.z-dn.net/files/dcd/f1ac794a99d50d60d6db85693aa9297c.jpg)
Answers
Answered by
0
Answer:
1/Rp= 1/6+1/2
1/Rp=4/6
1/Rp=2/3
Rp=3/2
Rs=3/2+6
Rs=15/2
Rs=7 1/2(d)
Answered by
1
Answer:
d) 7*1/2 Ω
Explanation:
It is given that the 6Ω & 2Ω resistor are in parallel . They are in series combination with 6Ω resistor .
We know that ,(In parallel)
1/Req = 1/6 + 1/2
= (1 + 3)/6
Req = 6/4 = 3/2Ω
Also,(In series)
Req = 3/2 + 6
= 15/2 = 7*1/2Ω
Similar questions