Question

pLeAse AnSwEr ThiS QuEsTiON ❣️❣️

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Answer 1

Answer:

hope it is help ful to u. .

Step-by-step explanation:

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Answer 2

Answer:

[Figure in the attachment]

Given –

• A point above the lake is Q.
• The distance between the point P and Q is 200 m.
• Angle of elevation from the point Q to the cloud is 30°.
• The angle of depression from the point Q to the reflection of the cloud in the lake is 60°.

To Find –

• Height of the cloud.

Solution –

We know that the length PQ is 200m. Hence, AB = 200 m.

Now, height of cloud = AB + BC.

We know the length of AB, We need to find BC.

In ∆ QBC,

tan ∅ = Perpendicular/Base

Hence, tan 30° = BC/QB.

➸ tan 30° = x/QB

[Assumed BC as x]

➸ 1/√3 = x/QB

➸ QB = √3 x ....k1)

In ∆ QBD,

tan ∅ = Perpendicular/Base

Hence, tan 60° = BD/QB

➸ √3 = (200 + AD)/QB

➸QB√3 = 200 + AD

➸ QB = (200 + AD)/√3 ....(2)

Equating equation 1 and 2,

➸ QB = √3 x = (200 + AD)/√3

➸ 3 x = 200 + AD

[AD = 200 + x]

➸ 3 x = 200 + 200 + x

➸ 3 x = 400 + x

➸ 3 x - x = 400

➸ 2 x = 400

➸ x = 400/2

➸ x = 200

Hence, Height of cloud = 200 + x = 200 + 200 = 400 m.