Question

please answer this question ​

Answer 1

ANSWER OF 11.

Initial speed of airplane u=0 m/s

Acceleration of the plane a=3.2 m/s

2

and time taken t=3.28 s

Using formula, distance covered S=ut+

2

1

at

2

⇒ S=0(32.8)+0.5(3.2)(32.8)

2

=1721.3∼1720m.

ANSWER OF 12.

a=0.1m/s

2

and t=2min=120s

(A)v=u+at=0+0.1×120

⟹v=12m/s

(b)s=ut+

2

1

at

2

⟹s=0+

2

1

×0.1×(120)

2

⟹s=720m.

I HOPE IT MAY HELP U..

Answer 2

Answer:

                         Here you go mate

Explanation:

ANSWER OF 11.

                 Initial speed of airplane u=0 m/s

                Acceleration of the plane a=3.2 m/s

               and time taken t=3.28 s

               Using formula, distance covered S=ut+$\frac{at^{2} }{ 2}$

               ⇒ S=0(32.8)+0.5(3.2)(32.8)(3.28)

                =1721.344∼1721m.

ANSWER OF 12.

                   a = 0.1m/s^2

            and t = 2min = 120s

                  v =  u+at=0+0.1×120

             ⟹v = 12m/s

                      s = ut+$\frac{at^{2} }{2}$

                  ⟹s = 0+(1/2) (0.1)(120)(120)

                  ⟹s = 720m.

I HOPE IT MAY HELP U..