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By pythagoras theorem, CD^2 = AC^2 + AD^2
13^2 = 12^2 + AD^2
AD^2 = 169 - 144 = 25
AD = 5 m
Sec theta = H/B = CD/ AD = 13/5
Cosec theta = H/P = CD/ AC = 13/12
(sec theta + cosec theta) = 13/5 + 13/12 = 221/60
Option B). 221/60 is correct.
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