Question

Please answer this question

Answer 1

Step-by-step explanation:

In this figure

given that angle A =angle 1

We have to prove that triangleBDE~triangleBCA

Proof in ∆BDE and ∆BCA

ANGLE 1=ANGLE A

AND ANGLE B = ANGLE C. (COMMON IN BOTH ∆)

SO FROM AA PROPERTY ∆BDE~∆BCA

HENCE PROVED

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