Question

please answer this question.​

Answer 1

1. Area of triangle ⇒ $\frac{1}{2} bh$

According to this formula, we solve it like this ⇒

a)

Base = 13 cm

Height = x

Area = 104 cm²

So height = x

$\frac{1}{2}*13*x=104$

$\frac{13}{2} *x = 104$

$x = 104*\frac{2}{13}$

$x = 16$

∴ Height = 16 cm

b)

Base = y

Height = 17 dm

Area = 153 dm²

So base = x

$\frac{1}{2}*y*17=153$

$\frac{17}{2}*y=153$

$y = 153*\frac{2}{17}$

$y=18$

∴ Base = 18 dm

c)

Base = 105 cm

Height = a

Area = 420 cm²

So height  = a

$\frac{1}{2}*105*a=420$

$\frac{105}{2} *a=420$

$a =420* \frac{2}{105}$

$a=8$

∴ Height = 8 cm

d)

Base = t

Height = 3.2 m

Area = 23.04 m²

So base = t

$\frac{1}{2}*t*3.2=23.04$

$1.6*t =23.04$

$t = 14.4$

∴ Base = 14.4 m

2. Area of parallelogram = $bh$

According to this formula, we solve it like this ⇒

a)

Base = 12 m

Height = p

Area = 144 m²

So height = p

$12*p=144$

$p = \frac{144}{12}$

$p = 12$

∴ Height = 12 m

b)

Base = d

Height = 12 m

Area = 216 m²

So base = d

$d*12=216$

$d = \frac{216}{12}$

$d = 18$

∴ Base = 18 m

c)

Base = 16 cm

Height = r

Area = 232 cm²

So height = r

$16*r=232$

$r=\frac{232}{16}$

$r = 14.5$

∴ Height = 14.5 cm

d)

Base = f

Height = 15 cm

Area = 246 cm²

So base = f

$f*15=246$

$f=\frac{246}{15}$

$f = 16.4$

∴ Base = 16.4 cm