Question

please answer this question ​

Answer 1

Step-by-step explanation:

Given -

• a + b + c = 0

To Show :-

• x^a²b-¹c-¹ . x^b²c-¹a-¹ . x^c²a-¹b-¹ = x³

As we know that :-

• a^p . a^q = a^p+q

Now,

➠ x^a²b-¹c-¹ . x^b²c-¹a-¹ . x^c²a-¹b-¹

➠ x^a²-¹-¹ + b²-¹-¹ + c²-¹-¹

➠ x^a^0 + b^0 + c^0 (a^0 = 1)

➠ x^¹+¹+¹

➠ x³

x^a²b-¹c-¹ . x^b²c-¹a-¹ . x^c²a-¹b-¹ = x³

Hence,

LHS = RHS