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80 degree is the answer
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Step-by-step explanation:
construction : draw a line cm which is parllel to AB
now, mc|| AB
<Qmc = <mBA =105° ( corresponding angle)
<Qmc and <pcm are interior angle of same side of transversal I .e.
<Qmc + <pcm = 180° ( because sum of interior angle of same side of transversal is 180°)
105° + < pcm = 180°
<PCM = 75°
similarly <BAC and <MCA are interior angle of same side of transversal
then
<BAC + <MCA = 180°
25° + <MCA = 180°
<MCA = 155°
now,
x+ <PCM + < MCA = 360°
x+ 75° + 155° = 360°
x + 230° = 360°
x= 360° - 230 °
x= 130°
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