Question

please answer this question

Answer 1

I hope that this answer helps you

Answer 2

In quadrilateral
ABCD, we have
AB=CD and AD=BC

Now join segment AC

Now in ΔABC and ΔACD, we have
AB=CD
---------------- already given
AD=BC
---------------- already given
and
AC=AC
---------------- common

Hence
ΔABC≡ΔACD
∴∠DAC=∠BCA
- both opposite equal sides
DC and AB
and
∴CD||AB
- as alternate angles are equal

∴∠DCA=∠CAB
- both opposite equal sides
AD and BC
∴AD||BC
- as alternate angles are equal

As opposite sides of quadrilateral are parallel,

ABCD is a parallelogram.