Question

please answer this question ​

Answer 1

Answer:

Given that,

The equation is,

2(a²+b²)x²+2(a+b)x+1=0

Since,a and b are distinct real numbers,

Then the determinant is,

D=b²-4ac

D=4(a+b)²-8(a²+b²)(1)

D=4(a²+b²+2ab-8a²-8b²

D=4a²+4b²+8ab-8a²-8b²

D=-4a²-4b²+8ab

D=-4(a²+b²-2ab)

D=-4(a-b)²<0

So, The equation has no real roots.

Explanation:

Hope it helps you.....