Question

please answer this question ​

Answer 1

✪ᴀɴsᴡᴇʀ✪

• $\large{\boxed{\boxed{ a = 1}}}$

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

GIVEN

• $(a-b), a, (a+b)$ are zeroes of cubic polynomial

$\:\:\:\:\:\:\:\:\:\:2x^3 - 6x^2 + 5x - 7$

CALCULATION

We have,

$sum\:of\:zeroes = - \frac{coeff\:of\:x^2}{coeff\:of\:x^3}$

$\implies (a-b)+ a+(a+b) = - \frac{-6}{2}$

$\implies a-b+ a+a+b = 3$

$\implies 3a = 3$

$\implies a = 1$