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Step-by-step explanation:
i) AB IS PARALLEL TO FE GIVEN IN FIGURE
THEREFORE angle ABC = angle EFD (alternate angles are equal)
also from figure ..1
angle ACB = angle EDF ..2
and AC=DE ..3
there fore triangle ABC is congruent to triangle EFD by AAS congruency criterion using 1, 2, 3
there fore by C.P.C.T- corresponding parts of congruent triangles
AB=FE proved
ii) again using CPCT
BC=DF
BC-CD=DF-CD ( equals subtracted by the same thing are equal )
BD=CF proved
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