Question

please answer this question ​

Answer 1

Question : 5

a) (-$\frac{4}{3}$ × $\frac{6}{4}$) + $\frac{7}{2}$ - ($\frac{6}{4}$ × ($\frac{8}{9}$

= -2 + $\frac{7}{2}$ - $\frac{4}{3}$

= $\frac{-12+21+8}{6}$

= $\frac{1}{6}$

b) $\frac{4}{5}$ × (- $\frac{6}{5}$) - ($\frac{4}{5}$ × ($\frac{3}{2}$ +( ($\frac{1}{14}$ × ($\frac{2}{5}$ )

= $\frac{-12}{5}$ + $\frac{1}{35}$

= - $\frac{83}{5}$

Question : 6

a) The ages of Saachin and Soham are in the ratio 7:5.

Thus there ages are, sachin = 7x and soham =  5x

4 year hence their ages will be

Sachin’s age =  7x + 4

Soham’s age = 5x + 4

The ratio of their ages

$\frac{7x + 4}{5x + 4}$ = $\frac{4}{3}$

Solving this equation

x = 4

∴ Sachin's age = 7x = 28

∴ Soham's age = 4x = 16

b) Let the 2-digit number = 10x + y

∴ Sum of digits = x + y = 9                  ................................EQUATION 1

If digits are interchanged

New number = 10y + x

10y + x = 10x + y + 27                               ................................EQUATION 2

Solving equation 1 and 2

we get x = 3 , y = 6

∴ ORIGINAL NUMBER = 10x + y = 36