Question

please answer this question

Answer 1

Step-by-step explanation:

1cos4(θ)−cos4(θ)=1−2cos2(θ)

Multiply both sides by cos4(θ)

1−cos8(θ)=cos4(θ)−2cos6(θ)

Let u=cos2(θ)

1−u4=u2−2u3

u4−2u3+u2−1=0(1)

Since this is a degree 4 equation, it can have at most 4 solutions. That means that cos2(θ) can have at most 4 values that satisfy(1). Since only 4 values can be satisfied at max, and |R|≫4, your original equation is not true for the vast majority of θ values.

Answer 2

Refer the attachment

Hope this helps you........

mark as brainlest...........

..................❤️...........................................