Math, asked by niteshshaw723, 6 months ago

please answer this question ​

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Answered by Anonymous
11

Question :-

  •  =  \bf \: \huge  \frac{x - 1}{x - 2}  +  \frac{x - 3}{x - 4}  = 3  \frac{1}{3}

Solution :-

\bf  \implies \frac{( x- 1)(x - 4) + ( x- 3)( x- 2)}{(x - 2)(x - 4)}  =  \frac{10}{3}  \\  \bf \implies \:  \frac{ ({x}^{2}  - 5x + 4) + ( {x}^{2}  - 5 + 6)}{ ({x}^{2}  - 5x + 8)}   = \frac{10}{3}   \\  \bf \implies3({2x}^{2}  - 10x + 10 ) = 10( {x}^{2}  - 6x + 8) \\  \bf \implies3  \times 2( {x}^{2}  - 10x + 10) = 10( {x }^{2}  - 6x + 8) \\  \sf \: (by \:taking\: common)  \\  \bf \implies3 \times  \cancel2 \: ( {x}^{2}  - 5x + 5) =  \cancel{10}( {x}^{2}  - 6x + 8)  \\  \bf \implies3 {x}^{2}  - 15x + 15 = 5 {x}^{2}  - 30x + 40\\  \bf \implies \: 3 {x}^{2}  - 5 {x}^{2}  - 15x + 30x + 10 - 40 = 0 \\  \bf \implies \:  - 2 {x}^{2}   + 15x - 25 = 0  \\  \bf \implies \: 2 {x}^{2}  - 15 + 25 = 0 \\  \bf \implies2 {x}^{2}  - 10x - 5x + 25 = 0 \\  \bf \implies2x(x - 5) - 5( x- 5) = 0 \\  \bf \implies \: 2x - 5 = 0 \\   \bf \implies \: x =  \frac{5}{2}

Answered by Anonymous
3

Answer:

Thank you

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