Question

please answer this question​

Answer 1

Answer:

$\frac{secx - tanx}{secx+tanx}$

multiply and divide by secx- tanx

$\frac{secx - tanx}{secx+tanx}$×$\frac{secx - tanx}{secx+tanx}$=$\frac{(secx- tanx)^{2} }{secx^{2}-tanx^{2} }$

=$\frac{secx^{2} +tanx^{2} +2 secx tanx }{1}$         (using identity $secx^{2} -tanx^{2} =1$)

=1+$tanx^{2}$+$tanx^{2}$+2 secx tanx

=1+2$tanx^{2}$+2 secx tanx

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Answer 2

Answer:

the up answer is the correct answer