Question

please answer this question ​

Answer 1

Answer

given, 3/4 is a root of ax^2 + bx -6 = 0;

so,  a*(3/4)^2+b*3/4-6=0

      9a/16+3b/4=6

      36a+48b/64=6

      9a+12b/16=6

      9a+12b=96

       9a+12b-96=0

      3(3a+4b-32)=0

       3a+4b-32=0

       3a+4b=32----------(1)

given,-2 is a root of ax^2+bx-6=0

so, a*(-2)^2+b*(-2)-6=0

     4a-2b-6=0

       4a-2b=6

       2a-b=3--------(2)

equation(2)*4, we get,8a-4b=12-------(3)

adding (1)+(3), we get,

3a+4b+8a-4b=32+12

3a+8a=44

11a=44

a=4

put value of a in eq (2)

2*4-b=3

8-b=3

-b=-5

b=5

the required values of a and b are 4 and 5

Answer 2

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