Question

please answer this question ​

Answer 1

$\huge{\underbrace {\mathbb{\blue {SOLUTION..}}}}$

Given :-

${x}^{2} - (1 + \sqrt{2})x + \sqrt{2 = 0}$

⏩On Splitting the middle term,we get :-

${x}^{2} - \sqrt{2} x - x + \sqrt{2} = 0$

$( {x}^{2} - \sqrt{2} x) + ( - x + \sqrt{2} ) = 0$

⏩Taking common form each parentheses ,we get :-

$x(x - \sqrt{2}) - 1(x - \sqrt{2}) = 0$

$(x - \sqrt{2} )(x - 1) = 0$

⏩Using zero product property, we get :-

$x - \sqrt{2} = 0 \: or \: x - 1 = 0$

$x = \sqrt{2} \: or \:x = 1$

Therefore,

$x = 1 \: or \: \sqrt{2}$

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but in live in gujarat

Answer 2

Answer:

x=√2or x=1

Step-by-step explanation:

x^2-x-√2x+√2

x(x-1) -√2(x-1)=0

(x-1) (x-√2)=0

x-1=0 or x-√2=0

x=1 or x=√2